Ok thank you for your answer.
Le mardi 7 mars 2017 08:20:35 UTC+1, Alexandre Delegue a écrit :
>
> Hi,
>
> Executing this code
>
> Source.range(1, 4)
> .mapAsync(1, e -> CompletableFuture.supplyAsync(() -> {
> System.out.println("Num "+e);
> return e;
> }))
> .filter(any -> true)
> .take(1)
> .runWith(Sink.foreach(e -> { System.out.println("End "+e); }), mat);
>
>
> Will print
> Num 1
> End 1
> Num 2
>
> I don't understand why the async call in mapAsync is executed for number 2
> while the stream should be completed.
>
> This work fine
>
> Source.range(1, 4)
> .mapAsync(1, e -> CompletableFuture.supplyAsync(() -> {
> System.out.println("Num "+e);
> return e;
> }))
> .take(1)
> .runWith(Sink.foreach(e -> { System.out.println("End "+e); }), mat);
>
>
> So it seems that the filter method pull next element even if the stream is
> completed.
>
> Any idea? Is there a way to avoid that ?
>
> Thanks,
> Alexandre.
>
>
>
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