Hi,
Say that I have a stream with a consecutive integers source (1, 2, 3 ...),
and assume that toString returns a Future[String]:
source ~> bcast ~> toString.mapAsyncUnordered(8)(identity) ~> zip.in0
bcast ~> zip.in1
zip.out ~>
sink
My question is if mapAsyncUnordered will cause a shuffling, or will every
integer will be paired with its own toString representation?
Will the result be this:
"1" -> 1
"2" -> 2
"3" -> 3
...
or more like this:
"1" -> 7
"2" -> 1
"3" -> 3
...
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