Timak <[EMAIL PROTECTED]> writes: >> Finally, for characters of w bits, the histogram requires O(2^w log N) >> space in the general case, not O(w) as you say. > > My bad. I should be paying more careful when I post. I meant > O(2^w). Why O(2^w logN)?
To answer my own stupid question, LogN is for the counters of course. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
