I know counting sort can do in linear time but we dont need to use and
extra space.
as we do in case of counting sort.
I came up with this sol. but i think it's not stable so if u can find a
stable algo plzzz....
i=0;j=n-1;
while(i<j) {
if(a[i]==a[j]) {
if(a[i]==0)
i++;
else
j--; //ie equal to 1
continue; //ie go to while (i<j)
}
if(a[i]<a[j])
i++; //ie a[i] has to be zero only
else { //ie a[i] =1 and a[j] = 0 therefore swap them
swap(a[i],a[j]);
i++;
j--;
}
} //end of while
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