OK. I got this on the net. Too good. Time complexity is also O(n).
findloophead(x, y) {
a = x
b = y
while (next(a) != b) { /* while b is not loop head */
t = midpoint(a, b)
if (find(next(y), t, b)) { /* if t is in the loop */
b = t
else
a = t
}
return(b)
}
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