this code fragment may solve your problem:
 
---------------------------------------------
int x;
while (cin >> x) {
     // do something with x
}
---------------------------------------------

 
On 7/8/06, Munish Goyal <[EMAIL PROTECTED]> wrote:
u get the input from STDIN  and u end taking input when u read an EOF.

ofcourse the input will come thru a file to ur program but ur program need not know abt the file.
to ur prog. the input will be from stdin .
so just keep reading till EOF.


On 7/7/06, Arun <[EMAIL PROTECTED]> wrote:
i know this isnt a good place to ask this. but i have seen ppl discussing questions on mipt. anyway my basic qn is
consider this very simple problem.

http://acm.mipt.ru/judge/problems.pl?problem=001&CGISESSID=43c5f86726f4af1d4e688a981c65620c

i dont know where to get the input from. it says "List of integers ends with EOF". does it read from a file.(if so wat is the filename ? passed as arg?) .. if reading from STDIN, reading character by character (and then concat to form int)seems ugly and how do u input EOF?.



 



--
Munish Goyal
Denali Software Inc.
Bangalore
919342539813

, 133470973390.236450, 270};
int main(){m[2]--?m[0]*=4,m[1]*=5,main():printf(m);}

Don't attach in Microsoft (.DOC, .PPT) format
http://www.gnu.org/philosophy/no-word-attachments.html
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