It's not a 26 base number system. please read the problem properly. In a 26 base number system ab = 28. here ab is 27 because aa is not valid.

On 10/22/06, mahbubul hasan <[EMAIL PROTECTED]> wrote:
the best way is 26 base number system.
 
say: a=0, b=1...
 
so, abab
 
first reverse it: baba
 
so, baba = (1010)_26= 26^0*0 + 26^1*1 + 26^2*0 + 26^3*1 = ?
 
now u may say i assumed a=0 but it should have been a=1.
 
well... why dont u just add: 1 to each position that means, for 4 digit number add: 26^0 + 26^1 + 26^2 + 26^3
 
Mahbub
 


 
On 10/8/06, raja <[EMAIL PROTECTED] > wrote:

The problem is like this:

We represent lexicographic words with digits.

So,
a=1
b=2
c=3
.
.
.
.
z=26
ab=27
ac=28
.
.
.
az=51
bc=52
.
.
.

I am unable to find a general formula for this. It seems that I need as
mane sigma as many number of letters are (means as many for loops). Can
anybody propose a better answer?








--
Rajarshi Chowdhury
M.Tech, CSE
IIT Roorkee
([EMAIL PROTECTED])

http://chowdhuryrajarshi.blogspot.com

"It is not our abilities that show what we truly are ... it is our choices"

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