if u dont like O(n) space, a st.forward approach is sorting. this will take of any value of m, but ofcourse O(nlgn) time
On 11/1/06, ericunfuk
<[EMAIL PROTECTED]> wrote:
Dear all,
I have worked out the following algorithm for finding the majority
element(the element occurs more than n/2 times) of an array of n
elements :
Suppose that I have a subroutine that could find the median of an array
in theta(n) time, then:
the algorithm will be:
1.find the median of the array
2.check to see if it's the majority element by a single pass through
the array, and count its occurrence
Now, what if I want to find the element that occurs more than n/m times
in the array, where m is an arbitrary integer?How can I just modify the
above to get this new algorithm?It could be very straightforward, but i
got stuck on this,
Any hints, help appreciated!!
Thanks.
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- [algogeeks] majority element ericunfuk
- [algogeeks] Re: majority element shisheng li
- [algogeeks] Re: majority element ericunfuk
- [algogeeks] Re: majority element Arun
- [algogeeks] Re: majority element [EMAIL PROTECTED]
- [algogeeks] Re: majority element Arunachalam
