Hi,

Thanks for your reply.

Could you please explain it a little more detailed? Because I don't
see how exactly your proposed method solves my problem...

Thanks.

On 15 apr, 18:14, "chitta koushik" <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I think this can be done like.
> 1)Consider a point and check all the points around it which are
> different from it.
> 2)this can be done recursively...
> 3)if we get a pixel whose id is same as already visited one...don't
> consider that.
>
> On 4/15/07, elesser <[EMAIL PROTECTED]> wrote:
>
>
>
>
>
>
>
> > Hello,
>
> > In a program I am currently writing, I have a matrix (around 60000 x
> > 3) containing information about the pixels in an image: every row of
> > the matrix has information about 1 pixel. The first column contains
> > the pixel id and the following two columns contain the x and y
> > coordinates. If two rows have the same pixel id, this indicates that
> > these two pixels have exactly the same RGB values.
>
> > What I'm now trying to do is finding the smallest box in the image
> > that contains ALL the colors in the image, that is, that contains
> > every pixel with different RGB values at least one time. As far as I
> > know, this is done by comparing all x and y coordinates of all the
> > pixels with one another, looking for the smallest difference when
> > substracting the xy values from each other. The problem is that from
> > all identical pixel id's, one pixel has to be chosen that, overall, is
> > the closest to all other pixels.
>
> > Does anyone have any idea how to do this? I'm programming in MATLAB,
> > but code in C or C++ is fine.
>
> > Thanks.
>
> --
> ***************************************************************
> 30 years from now it doesn't matter which shoe you wore,which branded
> jean you wore..what all matters is WHAT YOU HAVE LEARNED AND HOW YOU
> HAVE USED IT.
>
> http://students.iiit.ac.in/~koushik_c- Tekst uit oorspronkelijk bericht niet 
> weergeven -
>
> - Tekst uit oorspronkelijk bericht weergeven -


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