Maybe this will work:
Starting from each vertex using BFS calculate the shortest path which
passes through vertexes from all the colors.

Best,
Ridvan



On Feb 24, 2:00 pm, "Ajinkya Kale" <[EMAIL PROTECTED]> wrote:
> On 2/24/08, Sticker <[EMAIL PROTECTED]> wrote:
>
>
>
>
>
> > I have a graph problem, which is different from the standard salesman
> > problem. I say it is more difficult.
>
> > In a graph, I have many vertexes with different colors. It is more
> > easier to think of each vertex as a shop selling only one goods and
> > vertexes with the same color selling the same goods. There are edges
> > between any two vertexes, with different distances.
>
> > You start at a specific position (different from any vertex), and have
> > a list of goods you need to buy. Figure out an optimal path with
> > shortest distance so you can get all the goods from the shops on the
> > path. You are not required to start and end at the same position and
> > edges and vertexes can be visited more than once if you want.
>
> > If there is no color on vertex, or in other words, each vertex sells a
> > distinct goods, then the above problem is identical to salesman
> > problem.
>
> I dont think that makes is identical to TSP. Cause in TSP you have to visit
> every node.
> But in this case you are given a list of goods and each vetex sells unique
> good.
> Also in TSP we have to return to the start point , but this is not the case
> here !
>
>  But now we have colors on vertexes and once a vertex with a
>
>
>
> > color is visited, you don't want to visit vertex with the same color
> > (which will only increase the total distance).
>
> > Since this problem is an extension of the standard salesman problem,
> > the practical solution is probably heuristic. The key is, what
> > heuristic strategy are you going to use.
>
> > I think the problem a bit and come up with a very naive solution:
>
> > For each vertex, calculate its distances to the closest vertexes with
> > other colors. For vertexes with the same color, choose the one with
> > the minimum total/average such distances. Then, only one vertex with a
> > color is remained in the graph. Then use heuristic strategy for
> > salesman problem.
>
> > any other idea?
>
> --
> Ciao,
> Ajinkya
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