when talking assimpotically it doesn't really matter what base is, as log_a(x) = log_b(x) * 1/log_b(a) and 1/log_b(a) is constant
On Thu, May 15, 2008 at 1:52 PM, amitabh chauhan <[EMAIL PROTECTED]> wrote: > actually base do not matters base 2 and base 10 are constant multiple of > each other so complexity remains same ( ya constant multiple do change )... > but its base 2 most often... > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
