Correct. It will not be exactly one traversal of each list. More precisely, in worst case each pointer will traverse one list completely and then another list from beginning to intersection point.
On Oct 11, 12:49 pm, ankur aggarwal <[email protected]> wrote: > *...@manisha > " one traversal for each of the lists" > * --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
