u can maintain the size.. and if you don't want that , at least memoize it.. it won't be O(n^2) then.
Rohit Saraf Sophomore Computer Science and Engineering IIT Bombay On Wed, Dec 9, 2009 at 9:12 PM, chitta koushik <[email protected]>wrote: > Though i couldn't get both ur approaches clearly , guess 2nd approach shud > take O(n^2) since you go to each node and find the size of left subtree . > > Or i shud be missing something. my bad can you explain your approaches > clearly. > > On Wed, Dec 9, 2009 at 8:20 PM, Rohit Saraf > <[email protected]>wrote: > >> do it iteratively either by: >> >> 1) If size of left tree is less than k, rotate the tree left. and so on >> till .....single while loop required for this. >> or >> 2) Start from head, if k is more than size of left-tree, go to left and >> continue searching.. other wise go right and search for k-size(left)-1 in >> right tree. All this can be implemented in a single while loop. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]<algogeeks%[email protected]> >> . >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<algogeeks%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
