If that is the representation, then the lists have to be reversed.
Otherwise the time goes up exponentially.

On Wed, Jan 27, 2010 at 5:19 PM, Algoose Chase <[email protected]> wrote:
> Condition:
> Can we do it keeping the original lists intact ? ie without reversing it.
> I mean , No recursion & no Reversing ... is it possible ?
>
> @kumar :
> 15234 is represented asĀ  1->5->2->3->4
>
> On Wed, Jan 27, 2010 at 4:09 PM, saurabh gupta <[email protected]> wrote:
>>
>> perhaps you mean,
>> reverse each link list O(n+m).
>> then sum each node with carryover maintained.
>>
>> On Wed, Jan 27, 2010 at 11:07 AM, Anurag Bhatia <[email protected]>
>> wrote:
>>>
>>> Let us take an example -
>>>
>>> Num 1 = 123456
>>> Num 2= 1234
>>> Link-1->Link-2->Link-3->Link-4->Link5->Link6
>>> Link-1->Link-2->Link-3->Link-4
>>>
>>> Add nodes into linkedlist 1 till either one of the list is not null.
>>> Make sure you process the carry in each iteration.
>>>
>>>
>>> --AB
>>>
>>>
>>> On Tue, Jan 26, 2010 at 9:47 PM, Algoose Chase <[email protected]>
>>> wrote:
>>> > conditions:
>>> > NO extra memory (@ stack or Heap) at all. No recursion.
>>> >
>>> > Any body has got any hint about how to get this done ?
>>> >
>>> >
>>> >
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