any algorithm to solve this problem...

ACM uses a new special technology of building its transceiver stations. This
technology is called
Modular Cuboid Architecture (MCA) and is covered by a patent of Lego
company. All parts of the
  transceiver are shipped in unit blocks that have the form of cubes of
exactly the same size. The cubes
  can be then connected to each other. The MCA is modular architecture, that
means we can select
  preferred transceiver configuration and buy only those components we need
.
  The cubes must be always connected "face-to-face", i.e. the whole side of
one cube is connected to the
  whole side of another cube. One cube can be thus connected to at most six
other units. The resulting
  equipment, consisting of unit cubes is called The Bulk in the
communication technology slang.
Sometimes, an old and unneeded bulk is condemned, put into a storage place,
and replaced with a new
one. It was recently found that ACM has many of such old bulks that just
occupy space and are no
longer needed. The director has decided that all such bulks must be
disassembled to single pieces to
save some space. Unfortunately, there is no documentation for the old bulks
and nobody knows the
exact number of pieces that form them. You are to write a computer program
that takes the bulk
description and computes the number of unit cubes.
Each bulk is described by its faces (sides). A special X-ray based machine
was constructed that is able
to localise all faces of the bulk in the space, even the inner faces,
because the bulk can be partially
hollow (it can contain empty spaces inside). But any bulk must be connected
(i.e. it cannot drop into
two pieces) and composed of whole unit cubes.

  Input
  There is a single positive integer T on the first line of input (equal to
about 1000). It stands for the
  number of bulks to follow. Each bulk description begins with a line
containing single positive integer
  F, 6 <= F <= 250, stating the number of faces. Then there are F lines,
each containing one face
  description. All faces of the bulk are always listed, in any order. Any
face may be divided into several
  distinct parts and described like if it was more faces. Faces do not
overlap. Every face has one inner
  side and one outer side. No side can be "partially inner and partially
outer".

  Each face is described on a single line. The line begins with an integer
number P stating the number of
points that determine the face, 4 <= P <= 200. Then there are 3 x P numbers,
coordinates of the points.
Each point is described by three coordinates X,Y,Z (0 <= X,Y,Z <= 1000)
separated by spaces. The
points are separated from each other and from the number P by two space
characters. These additional
spaces were added to make the input more human readable. The face can be
constructed by connecting
the points in the specified order, plus connecting the last point with the
first one.

The face is always composed of "unit squares", that means every edge runs
either in X, Y or Z-axis
direction. If we take any two neighbouring points X 1 ,Y 1 ,Z 1 and X 2 ,Y 2
,Z 2 , then the points will
always differ in exactly one of the three coordinates. I.e. it is either X 1
<> X 2 , or Y 1 <> Y 2 , or Z 1 <>Z 2 ,
 other two coordinates are the same. Every face lies in an orthogonal plane,
i.e. exactly one
coordinate is always the same for all points of the face. The face outline
will never touch nor cross
itself.

output
no. of unit cube in the bulk.

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