even my code would work if u make everything long long... i guess..

-Rohit


On Sun, Mar 7, 2010 at 3:15 PM, B |_ /\ C |<--D ! /\ /\/\ O /\| D <
[email protected]> wrote:

> long long r=N-K<K?(N-K):K;//chose small to miimize the loop
> int n=N-(N-r)+1;
> r=1;
>  long long res=1;
> for(long long i=n;i<=N;i++)
> {
>  res=res*i;
> res=res/r++;
> }
>  cout<<res<<endl;
> //-----------------------------------
> this is working ...code...
>
> On Sun, Mar 7, 2010 at 3:12 PM, Anil C R <[email protected]> wrote:
>
>> doesn't work for big numbers :P
>> Anil
>>
>>
>>
>> On Sun, Mar 7, 2010 at 2:53 PM, Rohit Saraf 
>> <[email protected]>wrote:
>>
>>> Here is the code if you want... i have not written it...
>>> it's directly copied from wiki :)
>>>
>>> unsigned long long choose(unsigned n, unsigned k) {
>>>     if (k > n)
>>>         return 0;
>>>
>>>     if (k > n/2)
>>>
>>>
>>>
>>>
>>>
>>>
>>>         k = n-k; // Take advantage of symmetry
>>>
>>>     long double accum = 1;
>>>     unsigned i;
>>>     for (i = 1; i <= k; i++)
>>>          accum = accum * (n-k+i) / i;
>>>
>>>     return accum + 0.5; // avoid rounding error
>>>
>>>
>>>
>>>
>>>
>>>
>>> }
>>>
>>> call choose(n-1,k-1);
>>>
>>>
>>> -Rohit
>>>
>>>
>>>
>>> On Sun, Mar 7, 2010 at 2:49 PM, Rohit Saraf <[email protected]
>>> > wrote:
>>>
>>>> The answer is simply  : (N-1) Choose (k-1)
>>>>
>>>>
>>>> -Rohit
>>>>
>>>>
>>>>
>>>> On Sun, Mar 7, 2010 at 2:11 PM, naga vinod kumar <
>>>> [email protected]> wrote:
>>>>
>>>>> How to solve this problem....
>>>>>
>>>>> http://www.codechef.com/problems/MARBLES/
>>>>>
>>>>>
>>>>> K.Naga Vinod Kumar
>>>>>
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