@ ashish ..  each team should play the other team at least once.
in merging .... that thing does not happen.

On Thu, Apr 8, 2010 at 9:42 AM, Ashish Mishra <[email protected]> wrote:

> Can it be done in more or less like merge sort way
> i.e 1. divide array into half
> 2. keep on doing it till u have two element left
> 3. arrang match between two and return winner
>
>
> On Wed, Apr 7, 2010 at 12:20 PM, «« ÄÑÜJ »» <[email protected]> wrote:
>
>> Can any one help me with this problem....
>>
>>
>> Its a divide and conquer problem where, there are n teams and each
>> team plays each opponent only once. And each team plays exactly once
>> every day. If n is the power of 2, I need to construct a timetable
>> allowing the tournament to finish in n-1 days...
>>
>> Any help would be appreciated.. thanks
>>
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>
>
> --
> How soon 'not now' becomes 'never'...
>
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