How about bucket sort.

On Wed, Apr 14, 2010 at 6:33 PM, Rohit Saraf <[email protected]>wrote:

> O(n log n) will be trivial.
>
> O(n) is required at any cost. (Consider the case with 501 "1"s and 499
> "0"'s)
>
> Ok, so u can make a hashmap with your integer as keys and frequency as the
> value.
>    No of keys will be between 2 and 500.   (=> Traversing through takes
> O(n) )
>    You will have to traverse the array exactly once => O(n)
> => O(n) solution.
>
> And it cannot be made better !
>
> --------------------------------------------------
> Rohit Saraf
> Second Year Undergraduate,
> Dept. of Computer Science and Engineering
> IIT Bombay
> http://www.cse.iitb.ac.in/~rohitfeb14<http://www.cse.iitb.ac.in/%7Erohitfeb14>
>
>
>
> On Wed, Apr 14, 2010 at 4:14 PM, Gauri <[email protected]> wrote:
>
>> Say If I have an array of 1,000 32-bit integers .And one of the value
>> is occuring 501 number of times or more in the array. Can someone help
>> me devise an efficient algorithm for the same ?
>>
>> Thanks & Regards
>> Gauri
>>
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