i think it can done like this, assume we have to find 'x' and 'y' wer s='x'+'y'
1) select ith node from tree (from beginning to end) 2) y= s - " ith number (node)" 3) now search for 'y' in BST if we found then there is node such that s= x + y; otherwise no.. -- Prashant Kulkarni || Lokaha Samastaha Sukhino Bhavanthu || || Sarve Jana Sukhino Bhavanthu || On Fri, May 14, 2010 at 2:47 AM, divya jain <[email protected]>wrote: > form a sorted array from inorder traversal of tree. now take to pointers > one to the beginning of array and other at the end. now check if the sum of > element is greater than reqd sum then increment 1st ptr. if their sum is > less than reqd sum then decrement 2nd ptr. if their sum is equal to the reqd > sum then this is the ans.. > hope it will work.. > > > On 13 May 2010 20:11, jalaj jaiswal <[email protected]> wrote: > >> given a bst... find two nodes whose sum is equal to a number k ... in O(n) >> time and constant space... >> >> -- >> With Regards, >> Jalaj Jaiswal >> +919026283397 >> B.TECH IT >> IIIT ALLAHABAD >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]<algogeeks%[email protected]> >> . >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<algogeeks%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
