#include<iostream>
//#define size(T)(*((char*)&T+1-*(char*)&T));
#define SIZEOF(var) (size_t)(&var+1) - (size_t)(&var)
using namespace std;
int main()
{
char a;
cout<<SIZEOF(a);
cin.sync();
cin.get();
return 0;
}
On Mon, May 31, 2010 at 1:14 PM, debajyotisarma
<[email protected]>wrote:
> This is not about algorithms,but related to C programming.
>
> How to implement sizeof operator?
>
> macro for this
> #define my_sizeof(a) (char*)(&a+1)-(char*)&a
>
> this works fine of variables
> int a;
> printf("%d",my_sizeof(a)); //or even for user defined
> structures
>
> but it will not work for data types
>
> like
>
> printf("%d",my_sizeof(int));
>
> so please get another solution.
> function will be preferable.not macro
>
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