@Antony: The 2 lists should have the same elements as well the number must be equal
On Wed, Jun 2, 2010 at 5:38 PM, Antony Vincent Pandian.S. <[email protected] > wrote: > @Raj > > What do you mean by identical? You are just concerned about the > presence of one element in another LL or you are concerned about the > equality of number of elements too? > > On 6/2/10, Raj N <[email protected]> wrote: > > @sharad kumar: But don't you think this'll consume a lot of space. Merge > > sort will give O(nlogn) complexity when a separate LL is used to store > the > > sorted elements but if we disbuild the same LL it'll be >O(n2). And also > wat > > do u mean by combining LL can u explain > > > > > > On Wed, Jun 2, 2010 at 6:48 AM, sharad kumar <[email protected] > >wrote: > > > >> @Raj:sorting can be done in O(nlogn)..sort both and compare both.or use > a > >> hash map to store all elements of one LL and then compare it with > >> other....or combine both the LL perform merge sort and start deleting > >> adjacent elements.if adjacent elements in equal count then LL are equal > >> and > >> at end of process we get an empty list..... > >> > >> > >> On Tue, Jun 1, 2010 at 11:55 PM, Raj N <[email protected]> wrote: > >> > >>> Hi all, > >>> Can someone suggest an efficient algorithm to check if 2 linked lists > >>> are identical. If 2 lists have to be sorted then there'll be a lot of > >>> space consumption for 2 separate linked lists. Can the whole process > >>> be done < O(n2) > >>> > >>> -- > >>> You received this message because you are subscribed to the Google > Groups > >>> "Algorithm Geeks" group. > >>> To post to this group, send email to [email protected]. > >>> To unsubscribe from this group, send email to > >>> [email protected]<algogeeks%[email protected]> > <algogeeks%[email protected]<algogeeks%[email protected]> > > > >>> . > >>> For more options, visit this group at > >>> http://groups.google.com/group/algogeeks?hl=en. > >>> > >>> > >> > >> > >> -- > >> yezhu malai vaasa venkataramana Govinda Govinda > >> > >> -- > >> You received this message because you are subscribed to the Google > Groups > >> "Algorithm Geeks" group. > >> To post to this group, send email to [email protected]. > >> To unsubscribe from this group, send email to > >> [email protected]<algogeeks%[email protected]> > <algogeeks%[email protected]<algogeeks%[email protected]> > > > >> . > >> For more options, visit this group at > >> http://groups.google.com/group/algogeeks?hl=en. > >> > > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to [email protected]. > > To unsubscribe from this group, send email to > > [email protected]<algogeeks%[email protected]> > . > > For more options, visit this group at > > http://groups.google.com/group/algogeeks?hl=en. > > > > > > -- > Sent from my mobile device > > Luv, > S.Antony Vincent Pandian > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<algogeeks%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
