I just checked out with so many possibilities and it is indeed matching. I
may not be correct though.

On Tue, Jun 8, 2010 at 7:50 PM, divya jain <[email protected]> wrote:

> how do u come to this formula T(n)=fib(n+2).. plz explain
>
>
> On 7 June 2010 21:19, saurabh gupta <[email protected]> wrote:
>
>> it might be referring to no of sequences (say T(n) ) with no consecutive
>> 1's
>> for n = 3, ans would be 5 viz.
>> 000, 001, 010, 100, 101
>>
>> T(n) =  fib(n+2)
>> where fib = Fibonacci series
>> which is interesting.
>>
>>
>> On Sat, Jun 5, 2010 at 11:40 AM, Raj N <[email protected]> wrote:
>>
>>> @sharad: What about 101 even it doesn't have two 1's in a row
>>>
>>>
>>> On Sat, Jun 5, 2010 at 8:59 AM, sharad kumar <[email protected]>wrote:
>>>
>>>> @rajn.can it be subsequence doesnt have one's too.hence 000,001,010,100
>>>> is required answer.
>>>>
>>>>
>>>> On Sat, Jun 5, 2010 at 12:13 AM, Raj N <[email protected]> wrote:
>>>>
>>>>> Hi,
>>>>> I came across this question to find the number of sequences of n
>>>>> binary digits that don't contain 2 1's in a row. I wanted to know what
>>>>> exactly this means. Is it like if n=3 then compute all binary numbers
>>>>> having 3 digits which don't have consecutive 1's 110, 011, 111 ??
>>>>> If not help me understanding it.
>>>>> Thanks!!
>>>>>
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