is-isomorphic(t1, t2) {
t1ld = t1->left->data
t2ld = t2->left->data
//.....
//base case for null or replace by sentinels and check
if( t1ld == t2ld && t1rd == t2rd)
return is-isomorphic(t1ld, t2ld) && return is-isomorphic(t1rd, t2rd)
if (t1ld == t2rd && t1rd == t2ld)
return is-isomorphic(t1ld, t2rd) && return is-isomorphic(t1rd, t2ld)
return false;
}
On Wed, Jun 9, 2010 at 8:29 PM, divya jain <[email protected]> wrote:
> @vadivel and anand
>
> { 1,2,3 } is *isomorphic* to { 1,3,2 }
> { 1,2,3,4,5,6,7 } is *isomorphic* to { 1,3,2,7,6,4,5 }
> { 1,2,3,4,5,6,7 } is NOT *isomorphic* to { 1,3,2,4,5,6,7 }
>
> so its nt necessary that right and left will interchange. it may or may
> not. if all right and left are interchanged then it is mirror tree. i think
> ur code is for mirror tree and not isomorphic tree..
>
>
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