multiply the original number x=23.34563456

Anurag Sharma

On Wed, Jun 9, 2010 at 10:36 PM, Veer Sharma <[email protected]>wrote:

> One question:
>
> No x = 23.34563456
> temp = x X 10 = 233.4563456
> temp = temp - x = 210.11071104
> decimal part zero? No.
> Now multiply the no. with 100. Which no? original x (= 23.34563456) or
> new no. temp (=210.11071104)?
>
>
> On Jun 9, 8:12 pm, divya jain <[email protected]> wrote:
> > multiply the no. with 10 nd store in temp. now subtract no from temp.
> check
> > if the decimal part is zero if yes.  then 1st digit after decimal is
> > recurring. if no. multiply the no with 100 and repeat . if this time
> decimal
> > part is zero then 2 digits after decimal r recurring nd so on..
> >
> > On 8 June 2010 21:45, Veer Sharma <[email protected]> wrote:
> >
> >
> >
> > > You have a Numerator and Denominator. After division you might get a
> > > recurring decimal points float as the answer.
> >
> > > Problem is: You need to identify the recurring part for a given
> > > decimal no?
> > > For example 23.34563456 ...
> > > return 3456
> >
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