Its not a tough question.Basic arithmetics/algebra question.
A----------------C----------------------------B
Suppose speed of train from A =x
Suppose speed of train from B =y
They meet at C
1st train take a sec to reach C from B
CB=ax
2nd train take b sec to reach C from A
CA=bx
Time taken for 2nd train to reach C from B = ax/y
Time taken for 1st train to reach C from a = by/x
As they meet these 2 time will be same
ax/y=by/x
=>ax^2=by^2
=>x:y= √b : √a
On Thu, Jun 10, 2010 at 11:35 PM, Raj N <[email protected]> wrote:
> Can someone help me deriving this ?
> If 2 trains start at the same time from points A and B towards each
> other and after crossing they take a and b sec in reaching B and A
> respectively, then A's speed:B's speed=b^1/2:a^1/2
>
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