Break the link between the first and second items in each list. Link the first item in the first list to the second item in the second list, and link the first item in the second list to the first item in the first list.
The traversal is from the first item of the first list, through the second list, starting with the second item and ending with the first item, and then through the remainder of the first list starting at the second item and ending with the first item (if it is correct to say that you end traversing a circular list). Dave On Jun 11, 2:53 am, Raj N <[email protected]> wrote: > Hi, > I came across this statement that using circular lists, concatenation > can be done without traversing either list. The same case with freeing > the entire list. > Can someone elaborate on this ? -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
