@anand:its similar to reference an array element using pointer...*(p+i) which is imilar to &p[i] when u put *before & the value gets dereferenced and hence p+i takes place same concept
On Sun, Jun 20, 2010 at 3:27 PM, anand <[email protected]> wrote: > it caculate the sum of two numbers. > > #include<stdio.h> > int main() > { > int a=7,b=2,s; > char *p; > p=(char *)a; > s= (int)&p[b]; //adding a & b //////HOW???? > printf("sum=%d\n",s); > return 0; > > } > > can any one explain the code......?? > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<algogeeks%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- yezhu malai vaasa venkataramana Govinda Govinda -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
