hmm..... :-o

On Fri, Jul 2, 2010 at 5:57 PM, Dave <[email protected]> wrote:

> Yes. With a period of 16:
> 1/17 = 0.0588235294117647 0588235294117647 0588235294117647 ...
>
> Dave
>
> On Jul 2, 5:22 am, jalaj jaiswal <[email protected]> wrote:
> > @dave
> > is 1/17 recurring...??
> > @abhirup
> > now convert float to string ..only part after decimal
> >
> > now let the string be .346346346.....
> > take an auxilarry array a[0--9]..initialize it to zero
> > as you encounter update inceremnt a[s[i]-48]
> > wheneva you element in tha array becomes 2
> > store i-1
> > now from 0 to i-1 is the desired answer
> >
> >
> >
> >
> >
> > On Fri, Jul 2, 2010 at 3:45 PM, Abhirup Ghosh <[email protected]>
> wrote:
> > > Can you please elaborate on the solution you have with auxiliary array?
> >
> > > On Fri, Jul 2, 2010 at 3:53 AM, jalaj jaiswal <
> [email protected]>
> > > wrote:
> >
> > > > we are given with  Numerator and Denominator. After division we might
> get
> > > a
> > > > recurring decimal points float as the answer.
> > > > For example 23.34563456 ...
> > > > return 3456 i.e the recurring part
> >
> > > > i did it by converting the decimal part into string(itoa).. then a
> scan
> > > to
> > > > find the first repeated character ...then outputting the string upto
> that
> > > > location of first character-1
> > > >  i found first repeated character using an auxilarry array[0..9]..
> > > > total 3 scans.. O(n)
> >
> > > > any better solutions please ??
> > > > --
> >
> > > > With Regards,
> > > > Jalaj Jaiswal
> > > > +919026283397
> > > > B.TECH IT
> > > > IIIT ALLAHABAD
> >
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> > B.TECH IT
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-- 
With Regards,
Jalaj Jaiswal
+919026283397
B.TECH IT
IIIT ALLAHABAD

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