@Jalaj. I don't understand how your comment contributes to the
discussion. Please explain.

Dave

On Jul 2, 10:56 am, jalaj jaiswal <[email protected]> wrote:
> for count suppose if there are very big numbers ..then space will nt be
> efficient
>
>
>
>
>
> On Fri, Jul 2, 2010 at 7:05 PM, saurabh gupta <[email protected]> wrote:
> > @Dave,
> > for 2n+1 you can have a configuration where repeated nos may not be
> > adjacent
> > you need a block of 3 instead of 2.
>
> >  On Fri, Jul 2, 2010 at 6:04 PM, Dave <[email protected]> wrote:
>
> >> For problem 1, finding a number that is repeated just once is enough.
> >> Scan the array to see if there are two adjacent numbers that are
> >> equal. If so, that is your repeated number. Otherwise, look for the
> >> repeat in the first 5 numbers. O(n).
>
> >> Dave
>
> >> On Jul 1, 11:43 am, sharad <[email protected]> wrote:
> >> > 1.an array of 2n+1 elements is given .....one element is repeated n
> >> > times
> >> > and rest all are different.....find the no repeated.
> >> > 2.same question as above but this time other no's are not
> >> > different ..i.e
> >> > they can repeat.
>
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> > --
> > Man goes to doctor. Says he's depressed. Says life seems harsh and cruel.
> > Says he feels all alone in a threatening world where what lies ahead is
> > vague and uncertain. Doctor says "Treatment is simple. Great clown
> > Pagliacci is in town tonight. Go and see him. That should pick you up." Man
> > bursts into tears. Says "But, doctor...I am Pagliacci."
>
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> --
> With Regards,
> Jalaj Jaiswal
> +919026283397
> B.TECH IT
> IIIT ALLAHABAD- Hide quoted text -
>
> - Show quoted text -

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