@Jalaj. The original poster said, "P.S---do not give block reversal
method for array rotation ...."

Dave

On Jul 2, 10:54 am, jalaj jaiswal <[email protected]> wrote:
> reverse full array first
> then, reverse last k elemnts and initial n-k elements seperately
> this will do
> On Fri, Jul 2, 2010 at 8:34 PM, Ratnesh Thakur 
> <[email protected]>wrote:
>
>
>
>
>
> > correction..
> > a[j]=a[j-1] instead of a[i]=a[i-1]
>
> > On Fri, Jul 2, 2010 at 7:30 PM, Ratnesh Thakur 
> > <[email protected]>wrote:
>
> >> i think this should work.
>
> >> for(i=1;i<=k;i++)
> >> {
> >> var=a[n-1]
> >> for(j=n-1;j>=1;j--)
> >> a[i]=a[i-1]
> >> a[0]=var
>
> >> }
>
> >> On Fri, Jul 2, 2010 at 5:36 PM, Saurabh Ahuja 
> >> <[email protected]>wrote:
>
> >>> a[0] = a[2]
> >>> a[1] = a[3]
> >>> a[2] = a[4]
>
> >>> a[0] and a[1] has been changed
> >>> a[3] = a[0]
> >>> a[4] = a[1]
>
> >>> so this solution would not work.
>
> >>> On Fri, Jul 2, 2010 at 5:14 PM, Akash Gangil <[email protected]>wrote:
>
> >>>> wouldn't this work:
>
> >>>> for i in range(0,len)
> >>>>     a[i] = a[(i+2)%5];
>
> >>>> where len is the length of array
>
> >>>> On Sat, Jun 26, 2010 at 3:37 PM, sharad kumar <[email protected]
> >>>> > wrote:
>
> >>>>> i have to right rotate an array by k positions
> >>>>> 1 2 3 4 5 for k=2 o/p shud be
> >>>>> 3 4 5 1 2
>
> >>>>> P.S---do not give block reversal method for array rotation and soln
> >>>>> must be inplace.....plzz write ur logic also along with d code
>
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> >>>> --
> >>>> Best Regards
> >>>> Akash Gangil
>
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> --
> With Regards,
> Jalaj Jaiswal
> +919026283397
> B.TECH IT
> IIIT ALLAHABAD- Hide quoted text -
>
> - Show quoted text -

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