@amit: In this case, we can calculate the length of string S and T and
reverse the string whose length is smaller than the other. Then Take LCS of
it. To get the final answer.



On Mon, Jul 12, 2010 at 7:05 AM, Amit Jaspal <[email protected]>wrote:

> @ above Consider S="anand" T={'d','n'.'a'}
>
> LCS is "na" but the Answer is "and" . Here the order of characters don't
> matter as i have mentioned .
>
> One way is you can take LCS with every possible permutation of T but that
> would be exponential
>
>
> On Mon, Jul 12, 2010 at 3:23 PM, ankur aggarwal 
> <[email protected]>wrote:
>
>> i think ques is not complete..
>> otherwise above ans is rite.. i suppose..
>>
>> On Mon, Jul 12, 2010 at 10:00 AM, Anand <[email protected]> wrote:
>>
>>> you can use longest common subsequence algorithm to solve it.
>>>
>>> http://codepad.org/NDAeIpxR
>>>
>>>
>>> On Sun, Jul 11, 2010 at 9:32 AM, amit <[email protected]> wrote:
>>>
>>>> Given a set T of characters and a string S , find the minimum window
>>>> in S which will contain all the characters in T in complexity O(n) .
>>>>
>>>> Constraint : The characters may appear in any order
>>>>
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>>
>>
>>
>> --
>> With Regards
>>
>> Ankur Aggarwal
>>
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>
>
>
> --
> Amit Jaspal
> Btech IT IIIT- Allahabad
>
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