main()
{
char arr[]="abcde";
int r = 3,i,count;
int len;
len = sizeof(arr)/sizeof(arr[0]);
for(i=0;i<len-r;i++)
{
count = 0;
while(count < r)
{
printf("%c\t", arr[i+count]);
count++;
}
printf("\t\t");
}
}
http://codepad.org/3n1qdS2R
On Wed, Jul 14, 2010 at 11:51 AM, ashita dadlani <[email protected]> wrote:
> @ashish:yours is not a generalized solution.Here you are assuming that u
> know r=3.
> What if we need to generalize the solution?
>
>
> On Wed, Jul 14, 2010 at 11:58 PM, Ashish Goel <[email protected]> wrote:
>
>> for (int i=0;i<n-r+1;i++)
>> printf("%c%c%c ", a[i],a[i+1],a[i+2]);
>>
>>
>> Best Regards
>> Ashish Goel
>> "Think positive and find fuel in failure"
>> +919985813081
>> +919966006652
>>
>>
>>
>> On Wed, Jul 14, 2010 at 6:23 PM, ankit mahendru <
>> [email protected]> wrote:
>>
>>> Write the code to print combinations of a given array (n& r were given)
>>> e.g for abcde .r=3 ...print " abc", "bcd' "cde" etc
>>>
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>
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