can you show it diagrammatically

is the block square with side L or is it a plank of length L?

putting a plank of lenght L at the corner of square implies that the corner
side is L/sqrt(2) and the perpendicular falling onto this diagnal plank
would eat up (sqrt(3)/sqrt(2))L

so left over (ABCD is inner rectangle, and DEFG is outer than i am trying to
connect AD which is sqrt(2)L

is (sqrt(2)L-sqrt(3)/sqrt(2))L >0
yes, so i would need essentially minimum 2 planks.

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Best Regards
Ashish Goel
"Think positive and find fuel in failure"
+919985813081
+919966006652


On Tue, Jul 20, 2010 at 12:08 AM, Snoopy Me <[email protected]> wrote:

> Nice way to put it erappy, here is another way.
>
> A block of length L can be place at the corner of the outer square
> such that it makes a triangle so that two sides of the triangle is the
> corner sides of the square and the base of the triangle is the block.
> Now, on this block another block can be placed to reach the corner of
> the inner square.
>
>
>
>
>
> On Jul 19, 10:08 am, erappy <[email protected]> wrote:
> > Use the block of size L, use the diagonal of the block (diagonal would be
> > definitely > L ) to fit in between two square islands.
> >
> > Thanks,
> >
> > On Sun, Jul 18, 2010 at 11:38 PM, amit <[email protected]> wrote:
> > > Puzzle, A square Island surrounded by bigger square, and in between
> > > there is infinite depth water. The distance between them is L. The
> > > wooden blocks of L are given.
> > > The L length block can't be placed in between to cross it, as it will
> > > fall in water (just fitting).
> > > How would you cross using these L length blocks.
> >
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