it is
3*2^12 + 15*2^8 + 3*2^4 + 3
so it becomes
3<<12 + 15<<8 + 3<<4 +3.. let this equal to n
take
while(n){2010/8/4 Seçkin Can Şahin <[email protected]> > either count it with a for loop or if you are using C, use > __builtin_popcount(int x) > > or > > x is given > int count = 0; > for(int i=0; i<32;i++) count += (x & (1<<i)) != 0; > > > On Tue, Aug 3, 2010 at 12:04 PM, amit <[email protected]> wrote: > >> (3*4096+15*256+3*16+3). How many 1's are there in the binary >> representation of the result. >> >> Is there a quick way to count the number of set bits in this number >> manually??? >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]<algogeeks%[email protected]> >> . >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<algogeeks%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- With Regards, Jalaj Jaiswal +919026283397 B.TECH IT IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
