how about using hashing???

at the first collision we will know the repeated element....

worst case time here will be ( n/2 +1 )

On Fri, Aug 6, 2010 at 12:04 AM, Anand <[email protected]> wrote:

> http://codepad.org/8eDVyeBT
>
> Using XOR logic we can find Duplicates in O(n)
>
>
> On Thu, Aug 5, 2010 at 11:25 AM, ravindra patel 
> <[email protected]>wrote:
>
>> Your test case is wrong. With this pattern you can have at max n/3
>> occurrences of 1. The questions says that repeated element has n/2
>> occurrences
>>
>>
>> On Thu, Aug 5, 2010 at 8:37 PM, Manjunath Manohar <
>> [email protected]> wrote:
>>
>>> consider the test case of...
>>>
>>> 1 2 3 1...
>>>
>>> 1 repeated n/2 times and 2,3 are distinct n/2 elements
>>>
>>> for this the algo will not work
>>>
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-- 
regards

Apoorve Mohan

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