Gopinath's solution can be extended by adding one more logic. Do in-order
traversal, store it in an array or something. Keep resetting this
data-structure if you hit a right leaf or a non-increasing number.
Well we will need two such arrays, one for storing the current increasing
sequence and other for the previous best.


*"These are my principle. If you don't like, i have others."*


On Wed, Aug 11, 2010 at 1:44 PM, Divya Jain <[email protected]>wrote:

> @ above
> ur soln ll fail in situation like
>                           10
>                          /     \
>                       15       18
>                      /    \      /  \
>                     22   7  17  77
> the inorder is
> 22 15 7 10 17 18 77
> so the longest increasing sequence is 7-77
> but this is not a bst as 10 n 7 r nt connected
>
> On 24 June 2010 22:36, gopinath sikha <[email protected]> wrote:
>
>> We can find the solution in O(n) where n is number of nodes.
>> Do an in-order traversal of the binary tree. then scan through the numbers
>> and find the list and find the longest(increasing or decreasing) sequence.
>> That is the size of maximum size of BST in the given binary tree.
>>
>>
>> On Wed, Jun 23, 2010 at 11:40 AM, Raj N <[email protected]> wrote:
>>
>>> Find the maximum size Binary search tree in a binary tree??
>>>
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