@maxim . my algo is for array of equal sizes.Sorry I didn't notice the
unequal thing.

On Tue, Aug 17, 2010 at 10:09 AM, Maxim Mercury <[email protected]>wrote:

> above algo isnt handling unequal length arrays,
>
> On Aug 13, 10:06 pm, Nikhil Agarwal <[email protected]> wrote:
> > Check this code
> >
> > int med1,med2;
> > void  func(int a[], int x1, int x2, int b[], int y1, int y2){
> > int midx,midy;
> >  if((y2-y1+1)==2)
> > {
> > med1=max(a[x1],b[y1]);
> >  med2=min(a[x2],b[y2]);
> > return;}
> >
> >  midx=(x1+x2)/2;
> > midy=(y1+y2)/2;
> >  if(a[midx]>b[midy]){
> > x2=x2-(midy-y1);
> > y1=midy;
> >  }else{y2=y2-(midx-x1);
> > x1=midx;}
> >
> >  func(a,x1,x2,b,y1,y2);
> >
> > }
> >
> > med1 and med2 are two medians.
> >
> >
> >
>
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-- 
Thanks & Regards
Nikhil Agarwal
Senior Undergraduate
Computer Science & Engineering,
National Institute Of Technology, Durgapur,India
http://tech-nikk.blogspot.com
http://beta.freshersworld.com/communities/nitd

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