This doesn't work on "abb" for example. On Aug 22, 9:28 am, Ashish Goel <[email protected]> wrote: > use a array > arr[char]=count char represent say a-z > count is # of occurances > > while (*s!='\0') > { > arr[*s-'a']++; > if (arr[*s-'a']==1) lastchar=*s; > > } > > lastchar is the last non repeating char > > Best Regards > Ashish Goel > "Think positive and find fuel in failure" > +919985813081 > +919966006652 > > On Sun, Aug 22, 2010 at 3:30 PM, Saikat Debnath <[email protected]>wrote: > > > > > How to find last unique character in a given string. Unique character > > means non-repeated number. Give an optimized way. > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to [email protected]. > > To unsubscribe from this group, send email to > > [email protected]<algogeeks%2bunsubscr...@googlegroups > > .com> > > . > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en.
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