inline int decrease (int v) {
int decreasedVal = 0;
int counter = 0;
loop( v) and { decreasedVal = counter; counter++};
return decreasedValue;
}


Need to think a better way for subtracting one variable from other also

inline int subtract(int a, int b) {
        loop (b) decrease(a);
}


division ??? how to compare two variables?????





return a;
Best Regards
Ashish Goel
"Think positive and find fuel in failure"
+919985813081
+919966006652


On Tue, Aug 24, 2010 at 9:44 PM, CraZyBoY <[email protected]> wrote:

> You have an abstract computer, so just forget everything you know
> about computers, this one only does what I'm about to tell you it
> does. You can use as many variables as you need, there are no negative
> numbers, all numbers are integers. You do not know the size of the
> integers, they could be infinitely large, so you can't count on
> truncating at any point. There are NO comparisons allowed, no if
> statements or anything like that.
>
>  There are only four operations you can do on a variable.
> 1) You can set a variable to 0.
> 2) You can set a variable = another variable.
> 3) You can increment a variable (only by 1), and it's a post
> increment.
> 4) You can loop. So, if you were to say loop(v1) and v1 = 10, your
> loop would execute 10 times, but the value in v1 wouldn't change so
> the first line in the loop can change value of v1 without changing the
> number of times you loop.
>
> You need to do 3 things.
> 1) Write a function that decrements by 1.
> 2) Write a function that subtracts one variable from another.
> 3) Write a function that divides one variable by another.
> 4) See if you can implement all 3 using at most 4 variables. Meaning,
> you're not making function calls now, you're making macros. And at
> most you can have 4 variables. The restriction really only applies to
> divide, the other 2 are easy to do with 4 vars or less. Division on
> the other hand is dependent on the other 2 functions, so, if subtract
> requires 3 variables, then divide only has 1 variable left unchanged
> after a call to subtract. Basically, just make your function calls to
> decrement and subtract so you pass your vars in by reference, and you
> can't declare any new variables in a function, what you pass in is all
> it gets.
>
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