Sorry, this is not a good example.
Try this:
Assuming the sequence is 2, 1, 1, 1 and k = 3. The correct answer will
be 1, 1, 1. Run your code and see the result.

On Sat, Aug 28, 2010 at 1:54 PM, satish <[email protected]> wrote:
> @Adam
> i ran the program with n=4 and k=2 and sequence as 2,3,999,9999
> i got 10998(i.e999+9999).
> plz check it....
>
> On Sat, Aug 28, 2010 at 10:25 AM, Adam <[email protected]> wrote:
>>
>> Actually, your code just considers the only non-decreasing subsequence
>> which starts from a[0] and is the most 'LEFT' one in this situation
>> rather than all the possible subsequences.
>>
>> For example, we have such sequence as 2,3,999,9999, and k = 2.
>>
>> In this situation, your code will give the subsequence {2,3} as the
>> result rather than the true one {999,9999}.
>>
>> On Aug 28, 3:36 am, satish satish <[email protected]> wrote:
>> > @Rahul
>> >
>> > #include<stdio.h>
>> > #include<stdlib.h>
>> > int nondecresing_maxsum(int *a,int n,int k)
>> > {  int sum=0,i,count=k+1,prev_num=a[0],*dp,count1=0;;
>> >    dp=(int *)malloc(sizeof(int)*(k+1));
>> >    for(i=0;i<n;++i)
>> >      if(prev_num<=a[i])
>> >       {  sum+=a[i];
>> >          prev_num=a[i];
>> >                  dp[count1%(k+1)]=a[i];
>> >                  count1++;
>> >                  count--;
>> >             if(!count)
>> >             {  sum-=dp[(count1)%(k+1)];
>> >                    count++;
>> >             }
>> >           }
>> >    return sum;}
>> >
>> > int main()
>> > {  int *arr,arr_size,i,k;
>> >    printf("give array size and k");
>> >    scanf("%d%d",&arr_size,&k);
>> >    arr=(int *)malloc(sizeof(int)*(arr_size+1));
>> >    printf("give elements");
>> >    for(i=0;i<arr_size;++i)
>> >      scanf("%d",&arr[i]);
>> >     printf(" %d",nondecresing_maxsum(arr,arr_size,k));
>> >
>> > }
>> >
>> > this is my first post
>> > plz correct me if im wrong....
>> > but this wil not work if all array numbers r negetive...
>>
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