@aravind no aravind it's working plz run my code and check it

On Mon, Aug 30, 2010 at 12:12 AM, Aravind <[email protected]>wrote:

> @srinivas i think miracle will not be printed....as n||n is n , so m==p is
> n == -n and this is not possible.....
>
>
> On Mon, Aug 30, 2010 at 12:00 AM, srinivas reddy <[email protected]
> > wrote:
>
>> @ aravind i wrote the code without macro isn't right plz check it..
>>
>>
>> On Sun, Aug 29, 2010 at 11:56 PM, Aravind <[email protected]>wrote:
>>
>>> @srinivas the macro will replace the 'data' with 1 || 1 and this will
>>> make the if condition true and print miracle.
>>>
>>>
>>> On Sun, Aug 29, 2010 at 11:24 PM, srinivas reddy <
>>> [email protected]> wrote:
>>>
>>>> @aravind this is slight modification to your one and this is generalized
>>>> one if it is not the way plz inform me
>>>>
>>>> #include<stdio.h>
>>>> void main()
>>>> {
>>>> int m,n,p;
>>>> printf("enter data");
>>>> scanf("%d",&n);
>>>> m=n||n;
>>>> p=-n||-n;
>>>> if(m==p && n!=0)
>>>> printf("miracle");
>>>> }
>>>>
>>>> here i replace data with m and -data with n so the code is working
>>>> properlyy i think
>>>>
>>>>
>>>>
>>>> On Sun, Aug 29, 2010 at 11:04 PM, srinivas reddy <
>>>> [email protected]> wrote:
>>>>
>>>>> @aravind i think u are right code plzz
>>>>>
>>>>>
>>>>>
>>>>> On Sun, Aug 29, 2010 at 10:59 PM, Aravind <[email protected]
>>>>> > wrote:
>>>>>
>>>>>> #define int 1 ||
>>>>>> #define data 1 || 1
>>>>>>
>>>>>> having theses macros will print miracle....
>>>>>> if macros are allowed....
>>>>>>
>>>>>> On Sun, Aug 29, 2010 at 10:20 PM, Manjunath Manohar <
>>>>>> [email protected]> wrote:
>>>>>>
>>>>>>> it will never print..and @ above..the != will never be evaluated
>>>>>>> ..because of the short circuiting &&
>>>>>>>
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>
>
>
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