According to me we can apply the equatin method :
Let the missing number be y.
Let the duplicated no. be x.
1. then find the product of the 1 to 100 and the sum 1 to 100 :A
Product would be of the form...1 *2*3....x*......y*....100 : B
Sum : 1+2+3.....+x....+y.....+100
2. find the prduct of array elements : P
find the sum of array elemnts : S
3. then A/P = y/x
B-S = y-x
Now solve the equations
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