@dave:
your code is producing 4526 for input=24526 instead of 2456
Here's corrected code :)
/////////CODE///////////////
int function(int n){
int a[10]={0},temp=0,result =0;
while(n){ //reverse the number..
temp=10*temp+n%10;
n/=10;
}
n=temp;
while(n){ ///remove duplicate digits...
if(a[n%10]==0){
a[n%10]=1;
result=10*result+n%10;
}
n/=10;
}
return result;
}
///////////////END/////////////////////
On Wed, Sep 22, 2010 at 8:51 AM, Dave <[email protected]> wrote:
> @Saurabh: Doesn't your code turn 123 into 321? Try this:
>
> int function(int n)
> {
> int a[10]={0};
> int result=0;
> int place=1;
> while(n){
> if(a[n%10]==0){
> a[n%10]=1;
> result+=(n%10)*place;
> place*=10;
> }
> n/=10;
> }
> return result;
> }
>
>
> Dave
>
> On Sep 21, 3:12 pm, saurabh agrawal <[email protected]> wrote:
> > int function(int n){
> >
> > int a[10]={0};
> > int result =0;
> > while(n){
> > if(a[n%10]==0){
> > a[n%10]=1;
> > result=10*result+n%10;
> > }
> > n/=10;}
> >
> > return result;`
> >
> >
> >
> > }
> > On Wed, Sep 22, 2010 at 12:39 AM, Albert <[email protected]>
> wrote:
> > > Given a number find the number by eliminating the duplicate digits in
> > > the number..
> >
> > > for eg: 24526 ans is 2456
> > > .....
> >
> > > int function(int n)
> > > {
> >
> > > .
> > > .
> > > .
> >
> > > }
> >
> > > Give all sort of solutions to this problem.....
> >
> > > Efficiency in the code is important ....
> >
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