int minDiff(int arr[], int arr_size)
{
int min_diff = arr[1] - arr[0];
int max_element = arr[0];
int i;
for(i = 1; i < arr_size; i++)
{
if(arr[i] - max_element < min_diff)
min_diff = arr[i] - max_element;
if(arr[i] > max_element)
max_element = arr[i];
}
return min_diff;
}
On Mon, Sep 20, 2010 at 10:38 AM, Srinivas <[email protected]>wrote:
> 2 nos with min diff
> given an array of size n. find 2 numbers from array whose difference
> is least in O(n) w/o
> using xtra space( i mean constant space)
>
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Nishant Agarwal
Computer Science and Engineering
NIT Allahabad
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