int minDiff(int arr[], int arr_size)
{
  int min_diff = arr[1] - arr[0];
  int max_element = arr[0];
  int i;
  for(i = 1; i < arr_size; i++)
  {
    if(arr[i] - max_element < min_diff)
      min_diff = arr[i] - max_element;
    if(arr[i] > max_element)
         max_element = arr[i];
  }
  return min_diff;
}


On Mon, Sep 20, 2010 at 10:38 AM, Srinivas <[email protected]>wrote:

> 2 nos with min diff
> given an array of size n. find 2 numbers from array whose difference
> is least in O(n) w/o
> using xtra space( i mean constant space)
>
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*****************************************
Nishant Agarwal
Computer Science and Engineering
NIT Allahabad
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