check for this input {7,8,5,1,3,4}
On Sep 23, 10:36 pm, Rishi Agrawal <[email protected]> wrote:
> @Dave, I check for the values you suggested but the code worked fine. There
> were other errors in the code. I have rectified them now.
>
> The following code seems to be working fine and in O(n) time.
>
> #include <stdio.h>
> #include <stdlib.h>
> void find_two_mins(int array[], int size)
> {
> int i,t;
> int min1, min2;
> if(array[0] <= array[1]) {
> min1=array[0];
> min2=array[1];
> } else {
> min2=array[0];
> min1=array[1];
> }
> for (i=2; i<size; i++){
> t=array[i];
> if(t<=min1) {
> min2=min1;
> min1=t;
> continue;
> }
> if(t<=min2) {
> min2=t;
> }
> }
> printf("\nMin elements are 1: %d 2: %d", min1,min2);
> printf("\n Absolute difference between two minimum elements are %d\n\n",
> abs(min1-min2));
>
> }
>
> int main()
> {
> //int array[10]={ 9,2,3,4,1,7,5,6,8,0};
> //
> //int array[10]={3,3,1,33,88,9098,112,33455,678,1};
> //int array[10]={5,3,1,33,88,9098,112,33455,678,1};
> //int array[10]={2,3,21,33,88,9098,112,33455,678,12};
> int array[10]={3,2,21,33,88,9098,112,33455,678,12};
>
> find_two_mins(array,10);
> return 0;
>
>
>
>
>
>
>
> }
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