This problem is already solved.
ans=(x|1)+1

On Mon, Sep 27, 2010 at 5:15 PM, nishaanth <[email protected]> wrote:

> try x+8-(x&7 )
>
> On Sep 26, 4:47 am, Dave <[email protected]> wrote:
> > @Shrevan: I mistyped what I intended. Try answer = (x | 7) + 1;
> >
> > Dave
> >
> > On Sep 26, 5:51 am, Shravan <[email protected]> wrote:
> >
> > > @Dave
> > > Your answer will be always 2 irrespective of the value of 'x'.
> > > BTW I too didn't the question.
> >
> > > On Sep 26, 2:42 pm, Mahendran MaheM <[email protected]> wrote:
> >
> > > > sry...i dnt get the qstn clearly.....
> >
> > > > On Sat, Sep 25, 2010 at 10:18 PM, Dave <[email protected]>
> wrote:
> > > > > Simpler: answer = (x || 7) + 1
> >
> > > > > Dave
> >
> > > > > On Sep 25, 10:14 am, rajess <[email protected]> wrote:
> > > > > > scan last(left) 4 bits .if the bits are not 1000.make them
> 1000.else
> > > > > > scan from left till u find first one(1).make this bit 1.and make
> > > > > > last(left) bits as 1000
> >
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> >
> > > - Show quoted text -
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