@saurabh.nsit:

Consider the following array:

1 2 6 7
2 3 7 8
4 5 8 9
5 7 9 10

And the item to be searched is 6. As I understand it, using your approach
you will search 6 in only the second and third row, which will not give the
correct solution.
Hope this clears a few doubts.

@Gene:
Analysing the complexity of ur algo:

T(n) = 3*T(n/2) + O(1)

which is n^(log_2(3)) = n^1.6.

Cheers
Nikhil Jindal

On Sun, Sep 26, 2010 at 11:14 PM, saurabh singh <[email protected]>wrote:

> As you mentioned ultimately element to be searched should either be in row
> 'i' (ahead of [i,i] element) or in row i+1 (before [i+1,i+1] element). Since
> each row contain numbers in sorted order so u can do binary search on these
> two rows and ultimately the complexity will be O(logn) only
>
>  On Sun, Sep 26, 2010 at 7:34 PM, Nikhil Jindal <[email protected]>wrote:
>
>>
>>
>>  On Tue, Sep 21, 2010 at 6:05 PM, saurabh singh 
>> <[email protected]>wrote:
>>
>>> solution 1:
>>> use concept of quad-tree and do binary search in that tree
>>>
>>> solution 2:
>>> do binary search on major diagonal. ultimately u will narrow down to
>>> search for element in  2 rows. in these two rows again do binary search.
>>>
>>
>> How do you narrow down to two rows? Please explain.
>> By searching on the diagonal, you get two elements such that one is lesser
>> than the number being searched for and the next is greater. let them be i,i,
>> and i+1,i+1.
>>
>> So you remove the array from 0,0 to i,i and from i+1,i+1 to n-1,n-1. But
>> the number could be anywhere in the rest of the array
>>
>>
>>>
>>> any solution will lead you to O(log(n)) time
>>>
>>>
>>> On Tue, Sep 21, 2010 at 5:10 PM, jagadish <[email protected]>wrote:
>>>
>>>> Hi all,
>>>> Given a 2d array which is sorted row wise and column wise as well,
>>>> find a specific element in it in LESS THAN O(n).
>>>> PS: an O(n) solution would involve skipping a column or a row each
>>>> time from the search and moving accordingly.
>>>> Solution less than O(n) is desirable!
>>>>
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>>>
>>>
>>> --
>>> Thanks & Regards,
>>> Saurabh
>>>
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>
>
> --
> Thanks & Regards,
> Saurabh
>
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