One possible solution would be to create an array of pointers to the list..
array index indicates how many times the element occurs and the list gives
the elements.

On Sun, Oct 3, 2010 at 11:22 AM, sharad kumar <[email protected]>wrote:

> it will take same amount of memory na....key value is element and vaule is
> the amount of times element occurs.....
>
>
> On Sun, Oct 3, 2010 at 11:11 AM, mac adobe <[email protected]> wrote:
>
>> i think hash map takes lots of memory ...  please correct me if i am wrong
>> here ..
>>
>> anyways its a soluton but i would like to have a different solution .. :)
>>
>> --mac
>>
>>
>> On Sun, Oct 3, 2010 at 10:55 AM, sharad kumar <[email protected]>wrote:
>>
>>> cant u use a hash map buddy???
>>>
>>>   On Sun, Oct 3, 2010 at 10:35 AM, mac adobe <[email protected]>wrote:
>>>
>>>>  You are given a very long array of integers . Some number in this
>>>> integer array come 1 time , some 2 times some 3 times . create 3 different
>>>> arrays .
>>>> Array 1 will have numbers with numbers comming only1 time , Array 2 will
>>>> have numbers with numbers comming 2  times, Array 3 will have numbers with
>>>> numbers repearting 3 times ,
>>>>
>>>>
>>>> Can you extend the solution to create array_x with elements  repeating x
>>>> times ?
>>>>
>>>> thanks
>>>> --mac
>>>>
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>>>
>>>
>>>
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>>> yezhu malai vaasa venkataramana Govinda Govinda
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>
>
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> yezhu malai vaasa venkataramana Govinda Govinda
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-- 
Rgds,
Kusuma S

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