Sarad

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On Oct 6, 5:47 am, sharad kumar <[email protected]> wrote:
> int denom(int Coin[],int n,int amount)
> {
> for(i=0;i<n;++i)
> {
> c=Coin[i];
> for(j=c;j<=amount;++j)
> {
> den[j]+=d[j-c];
>
>
>
> }
> }
> return den[amount];
> }
> On Wed, Oct 6, 2010 at 4:43 AM, pre lak <[email protected]> wrote:
> > Hi all,
>
> > Pls help me with the solution to the following problem related to the coin
> > changing problem.
>
> > suppose that the available coins a ein the denominations c^0, c^1 , c^2...
> > c^k for some intgers  c>1 and k>=1. show tht the greedy algorithm always
> > yeilds an optimal solution
>
> > thanks in advance
> > Preethi
>
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> yezhu malai vaasa venkataramana Govinda Govinda

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