Are you kidding?
Did you test your solution?
Suppose, A = {1, 4, 5, 6, 2, 2}.
Sum of the elements is S=20, X_SUM = 6.
Result of your algo is (20-6)/2=7 instead if correct 2.
On 20 окт, 14:49, Mahesh_JNU <[email protected]> wrote:
> Just add the number of the array and let the sum is S. Its complexity is
> O(n).
> Now XOR all elements of the array and say the result is X_SUM.Its complexity
> is O(n).
> Now the duplicate element is = (S - X_SUM)/2
>
> On Wed, Oct 20, 2010 at 4:14 PM, Asquare <[email protected]> wrote:
> > @Anirvana - In context to the XOR method u suggested, could u plz
> > explain why does it so happen.. ??
>
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